shell script with awk line that doesnt execute a further shell command - PROBLEM solved

shell script with awk line that doesnt execute a further shell command - PROBLEM solved

Post by Peter Guya » Fri, 11 Aug 2006 21:30:31


Peter Guyan schrieb:

this works:
link=$5 "=" $6; dnr=$6; zaehler++; print "wget -O " "\"" zaehler "\"" "
" "\""link"\"" }' $pfad$zieldatei | bash

tnx
 
 
 

1. shell script with awk line that doesnt execute a further shell command

2. handling SIGINT in shell scripts when executing another shell script.

I have a simple shell script foo1.sh that invokes another shell script
foo2.sh, something like below:

#!/bin/sh
SIGINT_handler()
{
echo "## [$DATE_TIME] User interrupt ignored,"
continue
}
trap SIGINT_handler 2

...
./foo2.sh
...

----------
while executing foo1.sh, if the script receives SIGINT, how do I ignore
the SIGINT in foo2.sh ? somehow foo2.sh does not finish to completion
and is killed after receiving SIGINT. but foo1.sh is still executing.
Is there any way to trap this signal in the child script. ? Please
share your thots and inputs on this topic.
Regards,
Vikram Shekhar

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